25y^2-80y+64=0

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Solution for 25y^2-80y+64=0 equation: 



25y^2-80y+64=0

a = 25; b = -80; c = +64;
Δ = b2-4ac
Δ = -802-4·25·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{80}{50}=1+3/5$

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